Pass value to injected EJB
Tiptoe or tiphoof? Adjusting words to better fit fantasy races
How do scammers retract money, while you can’t?
Proof of work - lottery approach
Is expanding the research of a group into machine learning as a PhD student risky?
What happens if you roll doubles 3 times then land on "Go to jail?"
India just shot down a satellite from the ground. At what altitude range is the resulting debris field?
How can I get through very long and very dry, but also very useful technical documents when learning a new tool?
How easy is it to start Magic from scratch?
Go Pregnant or Go Home
Are student evaluations of teaching assistants read by others in the faculty?
You cannot touch me, but I can touch you, who am I?
Increase performance creating Mandelbrot set in python
Closest Prime Number
How did Doctor Strange see the winning outcome in Avengers: Infinity War?
How does buying out courses with grant money work?
For a non-Jew, is there a punishment for not observing the 7 Noahide Laws?
Do sorcerers' subtle spells require a skill check to be unseen?
Opposite of a diet
How can we prove that any integral in the set of non-elementary integrals cannot be expressed in the form of elementary functions?
Why escape if the_content isnt?
Is `x >> pure y` equivalent to `liftM (const y) x`
Where does the Z80 processor start executing from?
Avoiding estate tax by giving multiple gifts
Gears on left are inverse to gears on right?
Pass value to injected EJB
$begingroup$
I have an EJB application that consists of two beans, Bean1 and Bean2, where Bean2 is injected in Bean1.
Bean1 receives HTTP requests from the browser, calls a method in Bean2, gets the result, and sends the HTTP response.
Also, Bean1 has access to the HttpSession object, where the userId of the user that logged in is stored. Bean2 does NOT have access to the HttpSession object.
The application needs to log messages (using sl4j/logback, for example). It could log the message in Bean1 or Bean2 methods, and when it logs a message, it has to include the userId of the session in the log entry.
Since Bean2 doesn't have the userId, it needs to get it from Bean1. The question is what is the best way to achieve that. What I DON'T want to do is to add a userId field to each method in Bean2, as there are many Bean1s and Bean2s in the application, and it is not maintainable. Any suggestions will be welcome.
@Path("someurl")
@Produces(MediaType.APPLICATION_JSON)
@Consumes(MediaType.APPLICATION_JSON)
@Stateless
public class Bean1
@Context
HttpServletRequest httpRequest;
@Inject
private Bean2 bean2;
public Response someMethod1()
final HttpSession session = httpRequest.getSession();
// get the userId from the session
String s = bean2.someMethod2();
// return Response
@Stateless
public class Bean2
public String someMethod2()
// ....
return "something";
java dependency-injection
asked 2 mins ago
ps0604ps0604
11314
$endgroup$
add a comment |
$begingroup$
I have an EJB application that consists of two beans, Bean1 and Bean2, where Bean2 is injected in Bean1.
Bean1 receives HTTP requests from the browser, calls a method in Bean2, gets the result, and sends the HTTP response.
Also, Bean1 has access to the HttpSession object, where the userId of the user that logged in is stored. Bean2 does NOT have access to the HttpSession object.
The application needs to log messages (using sl4j/logback, for example). It could log the message in Bean1 or Bean2 methods, and when it logs a message, it has to include the userId of the session in the log entry.
Since Bean2 doesn't have the userId, it needs to get it from Bean1. The question is what is the best way to achieve that. What I DON'T want to do is to add a userId field to each method in Bean2, as there are many Bean1s and Bean2s in the application, and it is not maintainable. Any suggestions will be welcome.
@Path("someurl")
@Produces(MediaType.APPLICATION_JSON)
@Consumes(MediaType.APPLICATION_JSON)
@Stateless
public class Bean1
@Context
HttpServletRequest httpRequest;
@Inject
private Bean2 bean2;
public Response someMethod1()
final HttpSession session = httpRequest.getSession();
// get the userId from the session
String s = bean2.someMethod2();
// return Response
@Stateless
public class Bean2
public String someMethod2()
// ....
return "something";
java dependency-injection
asked 2 mins ago
ps0604ps0604
11314
$endgroup$
add a comment |
$begingroup$
I have an EJB application that consists of two beans, Bean1 and Bean2, where Bean2 is injected in Bean1.
Bean1 receives HTTP requests from the browser, calls a method in Bean2, gets the result, and sends the HTTP response.
Also, Bean1 has access to the HttpSession object, where the userId of the user that logged in is stored. Bean2 does NOT have access to the HttpSession object.
The application needs to log messages (using sl4j/logback, for example). It could log the message in Bean1 or Bean2 methods, and when it logs a message, it has to include the userId of the session in the log entry.
Since Bean2 doesn't have the userId, it needs to get it from Bean1. The question is what is the best way to achieve that. What I DON'T want to do is to add a userId field to each method in Bean2, as there are many Bean1s and Bean2s in the application, and it is not maintainable. Any suggestions will be welcome.
@Path("someurl")
@Produces(MediaType.APPLICATION_JSON)
@Consumes(MediaType.APPLICATION_JSON)
@Stateless
public class Bean1
@Context
HttpServletRequest httpRequest;
@Inject
private Bean2 bean2;
public Response someMethod1()
final HttpSession session = httpRequest.getSession();
// get the userId from the session
String s = bean2.someMethod2();
// return Response
@Stateless
public class Bean2
public String someMethod2()
// ....
return "something";
java dependency-injection
asked 2 mins ago
ps0604ps0604
11314
$endgroup$
I have an EJB application that consists of two beans, Bean1 and Bean2, where Bean2 is injected in Bean1.
Bean1 receives HTTP requests from the browser, calls a method in Bean2, gets the result, and sends the HTTP response.
Also, Bean1 has access to the HttpSession object, where the userId of the user that logged in is stored. Bean2 does NOT have access to the HttpSession object.
The application needs to log messages (using sl4j/logback, for example). It could log the message in Bean1 or Bean2 methods, and when it logs a message, it has to include the userId of the session in the log entry.
Since Bean2 doesn't have the userId, it needs to get it from Bean1. The question is what is the best way to achieve that. What I DON'T want to do is to add a userId field to each method in Bean2, as there are many Bean1s and Bean2s in the application, and it is not maintainable. Any suggestions will be welcome.
@Path("someurl")
@Produces(MediaType.APPLICATION_JSON)
@Consumes(MediaType.APPLICATION_JSON)
@Stateless
public class Bean1
@Context
HttpServletRequest httpRequest;
@Inject
private Bean2 bean2;
public Response someMethod1()
final HttpSession session = httpRequest.getSession();
// get the userId from the session
String s = bean2.someMethod2();
// return Response
@Stateless
public class Bean2
public String someMethod2()
// ....
return "something";
java dependency-injection
java dependency-injection
asked 2 mins ago
ps0604ps0604
11314
asked 2 mins ago
ps0604ps0604
11314
asked 2 mins ago
ps0604ps0604
11314
asked 2 mins ago
ps0604ps0604
11314
asked 2 mins ago
ps0604ps0604
11314
11314
add a comment |
add a comment |
0
active
oldest
votes
Your Answer
StackExchange.ifUsing("editor", function ()
return StackExchange.using("mathjaxEditing", function ()
StackExchange.MarkdownEditor.creationCallbacks.add(function (editor, postfix)
StackExchange.mathjaxEditing.prepareWmdForMathJax(editor, postfix, [["\$", "\$"]]);
);
);
, "mathjax-editing");
StackExchange.ifUsing("editor", function ()
StackExchange.using("externalEditor", function ()
StackExchange.using("snippets", function ()
StackExchange.snippets.init();
);
);
, "code-snippets");
StackExchange.ready(function()
var channelOptions =
tags: "".split(" "),
id: "196"
;
initTagRenderer("".split(" "), "".split(" "), channelOptions);
StackExchange.using("externalEditor", function()
// Have to fire editor after snippets, if snippets enabled
if (StackExchange.settings.snippets.snippetsEnabled)
StackExchange.using("snippets", function()
createEditor();
);
else
createEditor();
);
function createEditor()
StackExchange.prepareEditor(
heartbeatType: 'answer',
autoActivateHeartbeat: false,
convertImagesToLinks: false,
noModals: true,
showLowRepImageUploadWarning: true,
reputationToPostImages: null,
bindNavPrevention: true,
postfix: "",
imageUploader:
brandingHtml: "Powered by u003ca class="icon-imgur-white" href="https://imgur.com/"u003eu003c/au003e",
contentPolicyHtml: "User contributions licensed under u003ca href="https://creativecommons.org/licenses/by-sa/3.0/"u003ecc by-sa 3.0 with attribution requiredu003c/au003e u003ca href="https://stackoverflow.com/legal/content-policy"u003e(content policy)u003c/au003e",
allowUrls: true
,
onDemand: true,
discardSelector: ".discard-answer"
,immediatelyShowMarkdownHelp:true
);
);
Sign up or log in
StackExchange.ready(function ()
StackExchange.helpers.onClickDraftSave('#login-link');
);
Sign up using Google
Sign up using Facebook
Sign up using Email and Password
Post as a guest
Required, but never shown
StackExchange.ready(
function ()
StackExchange.openid.initPostLogin('.new-post-login', 'https%3a%2f%2fcodereview.stackexchange.com%2fquestions%2f216382%2fpass-value-to-injected-ejb%23new-answer', 'question_page');
);
Post as a guest
Required, but never shown
0
active
oldest
votes
0
active
oldest
votes
active
oldest
votes
active
oldest
votes
Thanks for contributing an answer to Code Review Stack Exchange!
- Please be sure to answer the question. Provide details and share your research!
But avoid …
- Asking for help, clarification, or responding to other answers.
- Making statements based on opinion; back them up with references or personal experience.
Use MathJax to format equations. MathJax reference.
To learn more, see our tips on writing great answers.
Sign up or log in
StackExchange.ready(function ()
StackExchange.helpers.onClickDraftSave('#login-link');
);
Sign up using Google
Sign up using Facebook
Sign up using Email and Password
Post as a guest
Required, but never shown
StackExchange.ready(
function ()
StackExchange.openid.initPostLogin('.new-post-login', 'https%3a%2f%2fcodereview.stackexchange.com%2fquestions%2f216382%2fpass-value-to-injected-ejb%23new-answer', 'question_page');
);
Post as a guest
Required, but never shown
Sign up or log in
StackExchange.ready(function ()
StackExchange.helpers.onClickDraftSave('#login-link');
);
Sign up using Google
Sign up using Facebook
Sign up using Email and Password
Post as a guest
Required, but never shown
Sign up or log in
StackExchange.ready(function ()
StackExchange.helpers.onClickDraftSave('#login-link');
);
Sign up using Google
Sign up using Facebook
Sign up using Email and Password
Post as a guest
Required, but never shown
Sign up or log in
StackExchange.ready(function ()
StackExchange.helpers.onClickDraftSave('#login-link');
);
Sign up using Google
Sign up using Facebook
Sign up using Email and Password
Sign up using Google
Sign up using Facebook
Sign up using Email and Password
Post as a guest
Required, but never shown
Required, but never shown
Required, but never shown
Required, but never shown
Required, but never shown
Required, but never shown
Required, but never shown
Required, but never shown
Required, but never shown
