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How not to print words that contain the user entered alphabets?
The Next CEO of Stack OverflowMaking a list from user inputAssigning sentiment to each tweet - Twitter trendEncryption and decryption using alphabetic shiftsParsing locally stored HTML filesSummarize a document as a key-phrase or key-wordsFrom a set of words, output all words that fit a string of random letters (like Scrabble)Code to implement the Jaro similarity for fuzzy matching stringsContest Solution: Remorseful Samprocess data with numpy seems rather slow than pure python?Find the longest word in set D that is a subsequence of string S
$begingroup$
I have a word list in file words.txt. I want to print only those words from the file that doesn't contain that word..output here works fine..but if i want to add more than one word like : 'e','b'..then how can i do so..becoz whenever i enter a single alphabet input like 'e'..then output is perfectly fine..but for more than one alphabet, it prints the entire actual list..any suggestions??
fin= open('C:\words.txt')
read=fin.readline()
word=read.strip()
index=0
letter =input('What letters to exclude? ')
while read:
while index<len(word):
if word[index]==letter:
break
index=index+1
else:
print(word)
read=fin.readline()
word=read.strip()
python-3.x
asked 10 mins ago
user3981user3981
1
New contributor
user3981 is a new contributor to this site. Take care in asking for clarification, commenting, and answering.
Check out our Code of Conduct.
$endgroup$
add a comment |
$begingroup$
I have a word list in file words.txt. I want to print only those words from the file that doesn't contain that word..output here works fine..but if i want to add more than one word like : 'e','b'..then how can i do so..becoz whenever i enter a single alphabet input like 'e'..then output is perfectly fine..but for more than one alphabet, it prints the entire actual list..any suggestions??
fin= open('C:\words.txt')
read=fin.readline()
word=read.strip()
index=0
letter =input('What letters to exclude? ')
while read:
while index<len(word):
if word[index]==letter:
break
index=index+1
else:
print(word)
read=fin.readline()
word=read.strip()
python-3.x
asked 10 mins ago
user3981user3981
1
New contributor
user3981 is a new contributor to this site. Take care in asking for clarification, commenting, and answering.
Check out our Code of Conduct.
$endgroup$
add a comment |
$begingroup$
I have a word list in file words.txt. I want to print only those words from the file that doesn't contain that word..output here works fine..but if i want to add more than one word like : 'e','b'..then how can i do so..becoz whenever i enter a single alphabet input like 'e'..then output is perfectly fine..but for more than one alphabet, it prints the entire actual list..any suggestions??
fin= open('C:\words.txt')
read=fin.readline()
word=read.strip()
index=0
letter =input('What letters to exclude? ')
while read:
while index<len(word):
if word[index]==letter:
break
index=index+1
else:
print(word)
read=fin.readline()
word=read.strip()
python-3.x
asked 10 mins ago
user3981user3981
1
New contributor
user3981 is a new contributor to this site. Take care in asking for clarification, commenting, and answering.
Check out our Code of Conduct.
$endgroup$
I have a word list in file words.txt. I want to print only those words from the file that doesn't contain that word..output here works fine..but if i want to add more than one word like : 'e','b'..then how can i do so..becoz whenever i enter a single alphabet input like 'e'..then output is perfectly fine..but for more than one alphabet, it prints the entire actual list..any suggestions??
fin= open('C:\words.txt')
read=fin.readline()
word=read.strip()
index=0
letter =input('What letters to exclude? ')
while read:
while index<len(word):
if word[index]==letter:
break
index=index+1
else:
print(word)
read=fin.readline()
word=read.strip()
python-3.x
python-3.x
asked 10 mins ago
user3981user3981
1
New contributor
user3981 is a new contributor to this site. Take care in asking for clarification, commenting, and answering.
Check out our Code of Conduct.
asked 10 mins ago
user3981user3981
1
New contributor
user3981 is a new contributor to this site. Take care in asking for clarification, commenting, and answering.
Check out our Code of Conduct.
asked 10 mins ago
user3981user3981
1
New contributor
user3981 is a new contributor to this site. Take care in asking for clarification, commenting, and answering.
Check out our Code of Conduct.
asked 10 mins ago
user3981user3981
1
asked 10 mins ago
user3981user3981
1
1
New contributor
user3981 is a new contributor to this site. Take care in asking for clarification, commenting, and answering.
Check out our Code of Conduct.
New contributor
user3981 is a new contributor to this site. Take care in asking for clarification, commenting, and answering.
Check out our Code of Conduct.
user3981 is a new contributor to this site. Take care in asking for clarification, commenting, and answering.
Check out our Code of Conduct.
add a comment |
add a comment |
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