Script that fixes YML SIDs to be simplified for production

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Script that fixes YML SIDs to be simplified for production














0












$begingroup$


I work with YML files that include SIDs and the following structure:



 title:
"2": "content a" # key: comment
"3": "content b" # key: comment
"4": "content c" # key: comment
"5": "content d" # key: comment
"6": "content e" # key: comment


Usually, I have to remove some strings (note I never remove the number 1 or 2) so my new file looks like this:



 title:
"2": "content a" # key: comment
"3": "content b" # key: comment
"5": "content d" # key: comment
"6": "content e" # key: comment


I need to rearrange the SIDs in order to have a sequence without any gap (in this case 2, 3, 4, 5, 6) independently on the content. For that reason I have written the following script. It works properly but I need to bring it into production so I need your help to reduce its complexity, make it clear and simpler or any advice you may have for a beginner (in both, Python and Stack Exchange).



import re, os

file=input ('YML file name: ')

#read the file and store its content as a list
os.chdir('/home/balaclava/Desktop/Scripts/YML fixer/')
rdfile= open(file)
cont=rdfile.readlines()
rdfile.close()

#list to store the reviewed strings
newfile=[]
newfile.append(cont[0]+cont[1])

#Get the second string SID as reference
numRegex = re.compile(r'd+')
act=numRegex.search(cont[1])
global refnum
refnum=int(act.group())

#Loop for each string (-2 due to the two first string are excluded)
for i in range(len(cont)-2):
act=numRegex.search(str(cont[i+2]))
temp=int(act.group())
#If the SID is correct, add item to newlist, else, fix it and add the item to the list.
if temp == (refnum+1):
newfile.append(cont[i+2])
else:
temp= (refnum+1)
change=numRegex.sub(str(temp), cont[i+2])
newfile.append(change)
refnum += 1

#overwrite the file with the newlist content
with open (file,'w') as finalfile:
finalfile.write(''.join(newfile))
finalfile.close()








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$endgroup$
















    0












    $begingroup$


    I work with YML files that include SIDs and the following structure:



     title:
    "2": "content a" # key: comment
    "3": "content b" # key: comment
    "4": "content c" # key: comment
    "5": "content d" # key: comment
    "6": "content e" # key: comment


    Usually, I have to remove some strings (note I never remove the number 1 or 2) so my new file looks like this:



     title:
    "2": "content a" # key: comment
    "3": "content b" # key: comment
    "5": "content d" # key: comment
    "6": "content e" # key: comment


    I need to rearrange the SIDs in order to have a sequence without any gap (in this case 2, 3, 4, 5, 6) independently on the content. For that reason I have written the following script. It works properly but I need to bring it into production so I need your help to reduce its complexity, make it clear and simpler or any advice you may have for a beginner (in both, Python and Stack Exchange).



    import re, os

    file=input ('YML file name: ')

    #read the file and store its content as a list
    os.chdir('/home/balaclava/Desktop/Scripts/YML fixer/')
    rdfile= open(file)
    cont=rdfile.readlines()
    rdfile.close()

    #list to store the reviewed strings
    newfile=[]
    newfile.append(cont[0]+cont[1])

    #Get the second string SID as reference
    numRegex = re.compile(r'd+')
    act=numRegex.search(cont[1])
    global refnum
    refnum=int(act.group())

    #Loop for each string (-2 due to the two first string are excluded)
    for i in range(len(cont)-2):
    act=numRegex.search(str(cont[i+2]))
    temp=int(act.group())
    #If the SID is correct, add item to newlist, else, fix it and add the item to the list.
    if temp == (refnum+1):
    newfile.append(cont[i+2])
    else:
    temp= (refnum+1)
    change=numRegex.sub(str(temp), cont[i+2])
    newfile.append(change)
    refnum += 1

    #overwrite the file with the newlist content
    with open (file,'w') as finalfile:
    finalfile.write(''.join(newfile))
    finalfile.close()








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    Balaclava is a new contributor to this site. Take care in asking for clarification, commenting, and answering.
    Check out our Code of Conduct.







    $endgroup$














      0












      0








      0





      $begingroup$


      I work with YML files that include SIDs and the following structure:



       title:
      "2": "content a" # key: comment
      "3": "content b" # key: comment
      "4": "content c" # key: comment
      "5": "content d" # key: comment
      "6": "content e" # key: comment


      Usually, I have to remove some strings (note I never remove the number 1 or 2) so my new file looks like this:



       title:
      "2": "content a" # key: comment
      "3": "content b" # key: comment
      "5": "content d" # key: comment
      "6": "content e" # key: comment


      I need to rearrange the SIDs in order to have a sequence without any gap (in this case 2, 3, 4, 5, 6) independently on the content. For that reason I have written the following script. It works properly but I need to bring it into production so I need your help to reduce its complexity, make it clear and simpler or any advice you may have for a beginner (in both, Python and Stack Exchange).



      import re, os

      file=input ('YML file name: ')

      #read the file and store its content as a list
      os.chdir('/home/balaclava/Desktop/Scripts/YML fixer/')
      rdfile= open(file)
      cont=rdfile.readlines()
      rdfile.close()

      #list to store the reviewed strings
      newfile=[]
      newfile.append(cont[0]+cont[1])

      #Get the second string SID as reference
      numRegex = re.compile(r'd+')
      act=numRegex.search(cont[1])
      global refnum
      refnum=int(act.group())

      #Loop for each string (-2 due to the two first string are excluded)
      for i in range(len(cont)-2):
      act=numRegex.search(str(cont[i+2]))
      temp=int(act.group())
      #If the SID is correct, add item to newlist, else, fix it and add the item to the list.
      if temp == (refnum+1):
      newfile.append(cont[i+2])
      else:
      temp= (refnum+1)
      change=numRegex.sub(str(temp), cont[i+2])
      newfile.append(change)
      refnum += 1

      #overwrite the file with the newlist content
      with open (file,'w') as finalfile:
      finalfile.write(''.join(newfile))
      finalfile.close()








      share







      New contributor




      Balaclava is a new contributor to this site. Take care in asking for clarification, commenting, and answering.
      Check out our Code of Conduct.







      $endgroup$




      I work with YML files that include SIDs and the following structure:



       title:
      "2": "content a" # key: comment
      "3": "content b" # key: comment
      "4": "content c" # key: comment
      "5": "content d" # key: comment
      "6": "content e" # key: comment


      Usually, I have to remove some strings (note I never remove the number 1 or 2) so my new file looks like this:



       title:
      "2": "content a" # key: comment
      "3": "content b" # key: comment
      "5": "content d" # key: comment
      "6": "content e" # key: comment


      I need to rearrange the SIDs in order to have a sequence without any gap (in this case 2, 3, 4, 5, 6) independently on the content. For that reason I have written the following script. It works properly but I need to bring it into production so I need your help to reduce its complexity, make it clear and simpler or any advice you may have for a beginner (in both, Python and Stack Exchange).



      import re, os

      file=input ('YML file name: ')

      #read the file and store its content as a list
      os.chdir('/home/balaclava/Desktop/Scripts/YML fixer/')
      rdfile= open(file)
      cont=rdfile.readlines()
      rdfile.close()

      #list to store the reviewed strings
      newfile=[]
      newfile.append(cont[0]+cont[1])

      #Get the second string SID as reference
      numRegex = re.compile(r'd+')
      act=numRegex.search(cont[1])
      global refnum
      refnum=int(act.group())

      #Loop for each string (-2 due to the two first string are excluded)
      for i in range(len(cont)-2):
      act=numRegex.search(str(cont[i+2]))
      temp=int(act.group())
      #If the SID is correct, add item to newlist, else, fix it and add the item to the list.
      if temp == (refnum+1):
      newfile.append(cont[i+2])
      else:
      temp= (refnum+1)
      change=numRegex.sub(str(temp), cont[i+2])
      newfile.append(change)
      refnum += 1

      #overwrite the file with the newlist content
      with open (file,'w') as finalfile:
      finalfile.write(''.join(newfile))
      finalfile.close()






      python beginner





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      Balaclava is a new contributor to this site. Take care in asking for clarification, commenting, and answering.
      Check out our Code of Conduct.










      share







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      Check out our Code of Conduct.








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      asked 3 mins ago









      BalaclavaBalaclava

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      New contributor




      Balaclava is a new contributor to this site. Take care in asking for clarification, commenting, and answering.
      Check out our Code of Conduct.





      New contributor





      Balaclava is a new contributor to this site. Take care in asking for clarification, commenting, and answering.
      Check out our Code of Conduct.






      Balaclava is a new contributor to this site. Take care in asking for clarification, commenting, and answering.
      Check out our Code of Conduct.




















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