Do I use Trie correctly for implementation of a phonebook?

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Do I use Trie correctly for implementation of a phonebook?














0












$begingroup$


I implemented a PhoneBook utilizing a Trie data structure.



Could I ask you to evaluate it?



Did I apply Trie correctly for such case or is it better to store data somehow else?



I'm looking not only for working solution but also for an optimal one in terms of run-time and storage.



From my calculations, it takes NlogT to add() and get() where N is a number of chars and T is a number of children.



Am I right?



Here is the logic



public final class PhoneBook 

private final Node name;

private final Node surname;

private final Comparator<Record> comparator;

public PhoneBook()
this.name = new Node();
this.surname = new Node();
comparator = (r1, r2) ->
int result = r1.getName().compareTo(r2.getName());
if (result == 0)
result = r1.getSurname().compareTo(r2.getSurname());
if (result == 0)
result = r1.getNumber().compareTo(r2.getNumber());


return result;
;


public void add(final Record record)
add(record.getName().toLowerCase(), record, name);
add(record.getSurname().toLowerCase(), record, surname);


public SortedSet<Record> get(final String prefix)
final String lc = prefix.toLowerCase();
final List<Record> recordsRetrievedByName = get(lc, name);
final List<Record> recordsRetrievedBySurname = get(lc, surname);
final SortedSet<Record> result = new TreeSet<>(comparator);
result.addAll(recordsRetrievedByName);
result.addAll(recordsRetrievedBySurname);
return result;


private List<Record> get(final String prefix, final Node ancestor)
Node node = ancestor;
for (final char c: prefix.toCharArray())
final Node child = node.children.get(c);
if (child == null)
return Collections.emptyList();

node = child;

return node.records;


private void add(final String str, final Record record, final Node ancestor)
Node node = ancestor;
for (final char c: str.toCharArray())
final Node child;
if (node.children.containsKey(c))
child = node.children.get(c);
else
child = new Node();
node.children.put(c, child);

child.records.add(record);
node = child;



private static final class Node

private final Map<Character, Node> children = new TreeMap<>();

private final List<Record> records = new ArrayList<>();






And the Record immutable object



public final class Record



private final String name;

private final String surname;

private final String number;

//constructor, getters, toString









share







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$endgroup$
















    0












    $begingroup$


    I implemented a PhoneBook utilizing a Trie data structure.



    Could I ask you to evaluate it?



    Did I apply Trie correctly for such case or is it better to store data somehow else?



    I'm looking not only for working solution but also for an optimal one in terms of run-time and storage.



    From my calculations, it takes NlogT to add() and get() where N is a number of chars and T is a number of children.



    Am I right?



    Here is the logic



    public final class PhoneBook 

    private final Node name;

    private final Node surname;

    private final Comparator<Record> comparator;

    public PhoneBook()
    this.name = new Node();
    this.surname = new Node();
    comparator = (r1, r2) ->
    int result = r1.getName().compareTo(r2.getName());
    if (result == 0)
    result = r1.getSurname().compareTo(r2.getSurname());
    if (result == 0)
    result = r1.getNumber().compareTo(r2.getNumber());


    return result;
    ;


    public void add(final Record record)
    add(record.getName().toLowerCase(), record, name);
    add(record.getSurname().toLowerCase(), record, surname);


    public SortedSet<Record> get(final String prefix)
    final String lc = prefix.toLowerCase();
    final List<Record> recordsRetrievedByName = get(lc, name);
    final List<Record> recordsRetrievedBySurname = get(lc, surname);
    final SortedSet<Record> result = new TreeSet<>(comparator);
    result.addAll(recordsRetrievedByName);
    result.addAll(recordsRetrievedBySurname);
    return result;


    private List<Record> get(final String prefix, final Node ancestor)
    Node node = ancestor;
    for (final char c: prefix.toCharArray())
    final Node child = node.children.get(c);
    if (child == null)
    return Collections.emptyList();

    node = child;

    return node.records;


    private void add(final String str, final Record record, final Node ancestor)
    Node node = ancestor;
    for (final char c: str.toCharArray())
    final Node child;
    if (node.children.containsKey(c))
    child = node.children.get(c);
    else
    child = new Node();
    node.children.put(c, child);

    child.records.add(record);
    node = child;



    private static final class Node

    private final Map<Character, Node> children = new TreeMap<>();

    private final List<Record> records = new ArrayList<>();






    And the Record immutable object



    public final class Record



    private final String name;

    private final String surname;

    private final String number;

    //constructor, getters, toString









    share







    New contributor




    Pavel is a new contributor to this site. Take care in asking for clarification, commenting, and answering.
    Check out our Code of Conduct.







    $endgroup$














      0












      0








      0





      $begingroup$


      I implemented a PhoneBook utilizing a Trie data structure.



      Could I ask you to evaluate it?



      Did I apply Trie correctly for such case or is it better to store data somehow else?



      I'm looking not only for working solution but also for an optimal one in terms of run-time and storage.



      From my calculations, it takes NlogT to add() and get() where N is a number of chars and T is a number of children.



      Am I right?



      Here is the logic



      public final class PhoneBook 

      private final Node name;

      private final Node surname;

      private final Comparator<Record> comparator;

      public PhoneBook()
      this.name = new Node();
      this.surname = new Node();
      comparator = (r1, r2) ->
      int result = r1.getName().compareTo(r2.getName());
      if (result == 0)
      result = r1.getSurname().compareTo(r2.getSurname());
      if (result == 0)
      result = r1.getNumber().compareTo(r2.getNumber());


      return result;
      ;


      public void add(final Record record)
      add(record.getName().toLowerCase(), record, name);
      add(record.getSurname().toLowerCase(), record, surname);


      public SortedSet<Record> get(final String prefix)
      final String lc = prefix.toLowerCase();
      final List<Record> recordsRetrievedByName = get(lc, name);
      final List<Record> recordsRetrievedBySurname = get(lc, surname);
      final SortedSet<Record> result = new TreeSet<>(comparator);
      result.addAll(recordsRetrievedByName);
      result.addAll(recordsRetrievedBySurname);
      return result;


      private List<Record> get(final String prefix, final Node ancestor)
      Node node = ancestor;
      for (final char c: prefix.toCharArray())
      final Node child = node.children.get(c);
      if (child == null)
      return Collections.emptyList();

      node = child;

      return node.records;


      private void add(final String str, final Record record, final Node ancestor)
      Node node = ancestor;
      for (final char c: str.toCharArray())
      final Node child;
      if (node.children.containsKey(c))
      child = node.children.get(c);
      else
      child = new Node();
      node.children.put(c, child);

      child.records.add(record);
      node = child;



      private static final class Node

      private final Map<Character, Node> children = new TreeMap<>();

      private final List<Record> records = new ArrayList<>();






      And the Record immutable object



      public final class Record



      private final String name;

      private final String surname;

      private final String number;

      //constructor, getters, toString









      share







      New contributor




      Pavel is a new contributor to this site. Take care in asking for clarification, commenting, and answering.
      Check out our Code of Conduct.







      $endgroup$




      I implemented a PhoneBook utilizing a Trie data structure.



      Could I ask you to evaluate it?



      Did I apply Trie correctly for such case or is it better to store data somehow else?



      I'm looking not only for working solution but also for an optimal one in terms of run-time and storage.



      From my calculations, it takes NlogT to add() and get() where N is a number of chars and T is a number of children.



      Am I right?



      Here is the logic



      public final class PhoneBook 

      private final Node name;

      private final Node surname;

      private final Comparator<Record> comparator;

      public PhoneBook()
      this.name = new Node();
      this.surname = new Node();
      comparator = (r1, r2) ->
      int result = r1.getName().compareTo(r2.getName());
      if (result == 0)
      result = r1.getSurname().compareTo(r2.getSurname());
      if (result == 0)
      result = r1.getNumber().compareTo(r2.getNumber());


      return result;
      ;


      public void add(final Record record)
      add(record.getName().toLowerCase(), record, name);
      add(record.getSurname().toLowerCase(), record, surname);


      public SortedSet<Record> get(final String prefix)
      final String lc = prefix.toLowerCase();
      final List<Record> recordsRetrievedByName = get(lc, name);
      final List<Record> recordsRetrievedBySurname = get(lc, surname);
      final SortedSet<Record> result = new TreeSet<>(comparator);
      result.addAll(recordsRetrievedByName);
      result.addAll(recordsRetrievedBySurname);
      return result;


      private List<Record> get(final String prefix, final Node ancestor)
      Node node = ancestor;
      for (final char c: prefix.toCharArray())
      final Node child = node.children.get(c);
      if (child == null)
      return Collections.emptyList();

      node = child;

      return node.records;


      private void add(final String str, final Record record, final Node ancestor)
      Node node = ancestor;
      for (final char c: str.toCharArray())
      final Node child;
      if (node.children.containsKey(c))
      child = node.children.get(c);
      else
      child = new Node();
      node.children.put(c, child);

      child.records.add(record);
      node = child;



      private static final class Node

      private final Map<Character, Node> children = new TreeMap<>();

      private final List<Record> records = new ArrayList<>();






      And the Record immutable object



      public final class Record



      private final String name;

      private final String surname;

      private final String number;

      //constructor, getters, toString







      java algorithm tree complexity trie





      share







      New contributor




      Pavel is a new contributor to this site. Take care in asking for clarification, commenting, and answering.
      Check out our Code of Conduct.










      share







      New contributor




      Pavel is a new contributor to this site. Take care in asking for clarification, commenting, and answering.
      Check out our Code of Conduct.








      share



      share






      New contributor




      Pavel is a new contributor to this site. Take care in asking for clarification, commenting, and answering.
      Check out our Code of Conduct.









      asked 4 mins ago









      PavelPavel

      1012




      1012




      New contributor




      Pavel is a new contributor to this site. Take care in asking for clarification, commenting, and answering.
      Check out our Code of Conduct.





      New contributor





      Pavel is a new contributor to this site. Take care in asking for clarification, commenting, and answering.
      Check out our Code of Conduct.






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      Check out our Code of Conduct.




















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