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Allocate Resource Effectively


Resource Pool implementation with ReentrantLock and ConditionMax heap in Javajava.util.concurrent bounded resuable resource implementationFacade pattern usage with JDBC-resource on GlassfishUsing PostgreSQL effectively with a banking appResource caching in Java with soft referencesSieve32Fast - A very fast, memory efficient, multi-threaded Sieve of EratosthenesDisposable resource: lazy allocationAndroid Internal Resource ReaderMinecraft resource calculator













-1












$begingroup$


I have module called printer allocator (PrinterAllocator) which will allocate the next available printer to the requester.



import java.util.ArrayList;
import java.util.Arrays;
import java.util.BitSet;
import java.util.List;

public class PrinterAllocator

private static final int TOTAL_AVAILABLE_PRINTERS = 25;
private BitSet bitSet = new BitSet( TOTAL_AVAILABLE_PRINTERS );

public PrinterAllocator()
List<Integer> unassignedPriters = new ArrayList<>( Arrays.asList( 1, 2, 3, 24 ) ); // but this array will be fetched from database
unassignedPriters.forEach( printerId -> bitSet.set( printerId - 1 ) );


public int getNextPrinter()
int index = bitSet.nextClearBit( 0 ) + 1;
bitSet.set( index );
return index + 1;


public boolean hasEnoughPrinters(int printersNeeded)
/* point 1*/
return bitSet.cardinality()+printersNeeded<=TOTAL_AVAILABLE_PRINTERS;





Point 1: I am unable to replace 'point 1' with following code



 return bitSet.cardinality()+printersNeeded<=bitSet.size()


(or)

return bitSet.cardinality()+printersNeeded<=bitSet.length();


Because bitSet.size() and bitSet.length() has a different meaning that is size() != length() != TOTAL_AVAILABLE_PRINTERS



Any better Idea to implement PrinterAllocator with/without bitset









share







New contributor




Dinesh Kumar is a new contributor to this site. Take care in asking for clarification, commenting, and answering.
Check out our Code of Conduct.







$endgroup$
















    -1












    $begingroup$


    I have module called printer allocator (PrinterAllocator) which will allocate the next available printer to the requester.



    import java.util.ArrayList;
    import java.util.Arrays;
    import java.util.BitSet;
    import java.util.List;

    public class PrinterAllocator

    private static final int TOTAL_AVAILABLE_PRINTERS = 25;
    private BitSet bitSet = new BitSet( TOTAL_AVAILABLE_PRINTERS );

    public PrinterAllocator()
    List<Integer> unassignedPriters = new ArrayList<>( Arrays.asList( 1, 2, 3, 24 ) ); // but this array will be fetched from database
    unassignedPriters.forEach( printerId -> bitSet.set( printerId - 1 ) );


    public int getNextPrinter()
    int index = bitSet.nextClearBit( 0 ) + 1;
    bitSet.set( index );
    return index + 1;


    public boolean hasEnoughPrinters(int printersNeeded)
    /* point 1*/
    return bitSet.cardinality()+printersNeeded<=TOTAL_AVAILABLE_PRINTERS;





    Point 1: I am unable to replace 'point 1' with following code



     return bitSet.cardinality()+printersNeeded<=bitSet.size()


    (or)

    return bitSet.cardinality()+printersNeeded<=bitSet.length();


    Because bitSet.size() and bitSet.length() has a different meaning that is size() != length() != TOTAL_AVAILABLE_PRINTERS



    Any better Idea to implement PrinterAllocator with/without bitset









    share







    New contributor




    Dinesh Kumar is a new contributor to this site. Take care in asking for clarification, commenting, and answering.
    Check out our Code of Conduct.







    $endgroup$














      -1












      -1








      -1





      $begingroup$


      I have module called printer allocator (PrinterAllocator) which will allocate the next available printer to the requester.



      import java.util.ArrayList;
      import java.util.Arrays;
      import java.util.BitSet;
      import java.util.List;

      public class PrinterAllocator

      private static final int TOTAL_AVAILABLE_PRINTERS = 25;
      private BitSet bitSet = new BitSet( TOTAL_AVAILABLE_PRINTERS );

      public PrinterAllocator()
      List<Integer> unassignedPriters = new ArrayList<>( Arrays.asList( 1, 2, 3, 24 ) ); // but this array will be fetched from database
      unassignedPriters.forEach( printerId -> bitSet.set( printerId - 1 ) );


      public int getNextPrinter()
      int index = bitSet.nextClearBit( 0 ) + 1;
      bitSet.set( index );
      return index + 1;


      public boolean hasEnoughPrinters(int printersNeeded)
      /* point 1*/
      return bitSet.cardinality()+printersNeeded<=TOTAL_AVAILABLE_PRINTERS;





      Point 1: I am unable to replace 'point 1' with following code



       return bitSet.cardinality()+printersNeeded<=bitSet.size()


      (or)

      return bitSet.cardinality()+printersNeeded<=bitSet.length();


      Because bitSet.size() and bitSet.length() has a different meaning that is size() != length() != TOTAL_AVAILABLE_PRINTERS



      Any better Idea to implement PrinterAllocator with/without bitset









      share







      New contributor




      Dinesh Kumar is a new contributor to this site. Take care in asking for clarification, commenting, and answering.
      Check out our Code of Conduct.







      $endgroup$




      I have module called printer allocator (PrinterAllocator) which will allocate the next available printer to the requester.



      import java.util.ArrayList;
      import java.util.Arrays;
      import java.util.BitSet;
      import java.util.List;

      public class PrinterAllocator

      private static final int TOTAL_AVAILABLE_PRINTERS = 25;
      private BitSet bitSet = new BitSet( TOTAL_AVAILABLE_PRINTERS );

      public PrinterAllocator()
      List<Integer> unassignedPriters = new ArrayList<>( Arrays.asList( 1, 2, 3, 24 ) ); // but this array will be fetched from database
      unassignedPriters.forEach( printerId -> bitSet.set( printerId - 1 ) );


      public int getNextPrinter()
      int index = bitSet.nextClearBit( 0 ) + 1;
      bitSet.set( index );
      return index + 1;


      public boolean hasEnoughPrinters(int printersNeeded)
      /* point 1*/
      return bitSet.cardinality()+printersNeeded<=TOTAL_AVAILABLE_PRINTERS;





      Point 1: I am unable to replace 'point 1' with following code



       return bitSet.cardinality()+printersNeeded<=bitSet.size()


      (or)

      return bitSet.cardinality()+printersNeeded<=bitSet.length();


      Because bitSet.size() and bitSet.length() has a different meaning that is size() != length() != TOTAL_AVAILABLE_PRINTERS



      Any better Idea to implement PrinterAllocator with/without bitset







      java bitset





      share







      New contributor




      Dinesh Kumar is a new contributor to this site. Take care in asking for clarification, commenting, and answering.
      Check out our Code of Conduct.










      share







      New contributor




      Dinesh Kumar is a new contributor to this site. Take care in asking for clarification, commenting, and answering.
      Check out our Code of Conduct.








      share



      share






      New contributor




      Dinesh Kumar is a new contributor to this site. Take care in asking for clarification, commenting, and answering.
      Check out our Code of Conduct.









      asked 5 mins ago









      Dinesh KumarDinesh Kumar

      11




      11




      New contributor




      Dinesh Kumar is a new contributor to this site. Take care in asking for clarification, commenting, and answering.
      Check out our Code of Conduct.





      New contributor





      Dinesh Kumar is a new contributor to this site. Take care in asking for clarification, commenting, and answering.
      Check out our Code of Conduct.






      Dinesh Kumar is a new contributor to this site. Take care in asking for clarification, commenting, and answering.
      Check out our Code of Conduct.




















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