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Deep copy of an unknown(ish) type in a templated linked list
$begingroup$
I have a templated linked list (Inventory), and I have instantiated a inventory object of type Item *
Inventory<Item*> myinv;
Item is an abstract base class, I have two other classes, Weapon and Armor which both publicly derive from the Item ABC.
I have instantiated a Weapon object:
Weapon * frost = new Weapon("Weapon", 100, 0.01, 100);
I have used my function PushFront(const T & data)
myinv.PushFront(frost);
The function copies over the pointer to said data into the new nodes m_data, instead of doing a deep copy
template<class T>
inline void Inventory<T>::PushFront(const T & data)
{
Node<T> * nn = new Node<T>;
nn->m_data = data; //Copies over pointer instead of calling an overloaded assignment operator
m_count += 1;
.
.
.
I cannot for the life of me figure out the syntax to get it to use an overloaded assignment operator, I can post more code to those of you that need it.
Thank you for any help.
c++
asked 44 secs ago
MikeMike
1
New contributor
Mike is a new contributor to this site. Take care in asking for clarification, commenting, and answering.
Check out our Code of Conduct.
$endgroup$
add a comment |
$begingroup$
I have a templated linked list (Inventory), and I have instantiated a inventory object of type Item *
Inventory<Item*> myinv;
Item is an abstract base class, I have two other classes, Weapon and Armor which both publicly derive from the Item ABC.
I have instantiated a Weapon object:
Weapon * frost = new Weapon("Weapon", 100, 0.01, 100);
I have used my function PushFront(const T & data)
myinv.PushFront(frost);
The function copies over the pointer to said data into the new nodes m_data, instead of doing a deep copy
template<class T>
inline void Inventory<T>::PushFront(const T & data)
{
Node<T> * nn = new Node<T>;
nn->m_data = data; //Copies over pointer instead of calling an overloaded assignment operator
m_count += 1;
.
.
.
I cannot for the life of me figure out the syntax to get it to use an overloaded assignment operator, I can post more code to those of you that need it.
Thank you for any help.
c++
asked 44 secs ago
MikeMike
1
New contributor
Mike is a new contributor to this site. Take care in asking for clarification, commenting, and answering.
Check out our Code of Conduct.
$endgroup$
add a comment |
$begingroup$
I have a templated linked list (Inventory), and I have instantiated a inventory object of type Item *
Inventory<Item*> myinv;
Item is an abstract base class, I have two other classes, Weapon and Armor which both publicly derive from the Item ABC.
I have instantiated a Weapon object:
Weapon * frost = new Weapon("Weapon", 100, 0.01, 100);
I have used my function PushFront(const T & data)
myinv.PushFront(frost);
The function copies over the pointer to said data into the new nodes m_data, instead of doing a deep copy
template<class T>
inline void Inventory<T>::PushFront(const T & data)
{
Node<T> * nn = new Node<T>;
nn->m_data = data; //Copies over pointer instead of calling an overloaded assignment operator
m_count += 1;
.
.
.
I cannot for the life of me figure out the syntax to get it to use an overloaded assignment operator, I can post more code to those of you that need it.
Thank you for any help.
c++
asked 44 secs ago
MikeMike
1
New contributor
Mike is a new contributor to this site. Take care in asking for clarification, commenting, and answering.
Check out our Code of Conduct.
$endgroup$
I have a templated linked list (Inventory), and I have instantiated a inventory object of type Item *
Inventory<Item*> myinv;
Item is an abstract base class, I have two other classes, Weapon and Armor which both publicly derive from the Item ABC.
I have instantiated a Weapon object:
Weapon * frost = new Weapon("Weapon", 100, 0.01, 100);
I have used my function PushFront(const T & data)
myinv.PushFront(frost);
The function copies over the pointer to said data into the new nodes m_data, instead of doing a deep copy
template<class T>
inline void Inventory<T>::PushFront(const T & data)
{
Node<T> * nn = new Node<T>;
nn->m_data = data; //Copies over pointer instead of calling an overloaded assignment operator
m_count += 1;
.
.
.
I cannot for the life of me figure out the syntax to get it to use an overloaded assignment operator, I can post more code to those of you that need it.
Thank you for any help.
c++
c++
asked 44 secs ago
MikeMike
1
New contributor
Mike is a new contributor to this site. Take care in asking for clarification, commenting, and answering.
Check out our Code of Conduct.
asked 44 secs ago
MikeMike
1
New contributor
Mike is a new contributor to this site. Take care in asking for clarification, commenting, and answering.
Check out our Code of Conduct.
asked 44 secs ago
MikeMike
1
New contributor
Mike is a new contributor to this site. Take care in asking for clarification, commenting, and answering.
Check out our Code of Conduct.
asked 44 secs ago
MikeMike
1
asked 44 secs ago
MikeMike
1
1
New contributor
Mike is a new contributor to this site. Take care in asking for clarification, commenting, and answering.
Check out our Code of Conduct.
New contributor
Mike is a new contributor to this site. Take care in asking for clarification, commenting, and answering.
Check out our Code of Conduct.
Mike is a new contributor to this site. Take care in asking for clarification, commenting, and answering.
Check out our Code of Conduct.
add a comment |
add a comment |
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