Calculating when trains will meet, iteratively and using OOPGenerically encapsulating random generators and distributions into a class templateGeneric pixel class to seamlessly alpha-blend and convert between different pixel structure layoutsTracker for object construction, copy, and movement
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Calculating when trains will meet, iteratively and using OOP
Generically encapsulating random generators and distributions into a class templateGeneric pixel class to seamlessly alpha-blend and convert between different pixel structure layoutsTracker for object construction, copy, and movement
$begingroup$
I've done a little bit of programming in the past, mostly just dabbling.
After a long time of not touching an IDE, I am getting back into it, with Visual Studio. I just threw this quick project together to make sure I remember how to use classes and objects before I start playing with bigger projects.
I would love a quick critique to make sure there arent any glaring poor practices that could develop into bad habbits in the future.
I know the standard way to solve this problem is just time = distance/(velA+velB), but what would the point of using objects be if i didnt have the objects do something and change their status in someway?
What do you think, looks good?
/*
The goal for this practice program is to solve the common math word problem below using classes and objects.
I feel that using iterations rather than the basic math formula to solve, although clearly less efficient, would be more true to thinking in terms of objects.
Train A, traveling X miles per hour (mph), leaves Westford heading toward Eastford, 260 miles away.
At the same time Train B, traveling Y mph, leaves Eastford heading toward Westford.
When do the two trains meet? How far from each city do they meet?
*/
#include "pch.h"
#include <iostream>
using namespace std;
class Train
public:
Train(int, int);
int getLocation();
void update();
private:
int location, velocity;
;
Train::Train(int loc, int vel) //to initialize the train object and set its location and velocity
location = loc;
velocity = vel;
int Train::getLocation() // returns the location of the train object
return location;
void Train::update() // updates the train object for one iteration
location += velocity;
int main()
int velA, velB, distance; //to take the values from the user input
int time; // to keep track of the number of iterations
// time is declared here so it can be used outside of the for loop
//input
cout << "Enter velocity of the train from Westford:n";
cin >> velA;
cout << "nnEnter velocity of the train from Eastford:n";
cin >> velB;
cout << "nnEnter the distance between Westford and Eastford:n";
cin >> distance;
//initialize each train
Train trainA(0, velA);
Train trainB(distance, 0 - velB); //location of trainB is distance because the distance between an x coordinate at 0 and another x coordinate is equal to the second x coordinate
//the velocity of trainB is the negative of velB because it is traveling in the opposite direction of trainA
//run the sim
for (time = 0; trainA.getLocation() < trainB.getLocation(); time++)
trainA.update();
trainB.update();
//output
cout << "nnThe Trains pass eachother after " << time << " hours."
<< "nAt that time, the Westford train is " << trainA.getLocation() << " miles from Westfordn"
<< "and the Eastford train is " << distance - trainB.getLocation() << " miles from Eastford.nn";
return 0;
c++ beginner c++17
New contributor
$endgroup$
add a comment |
$begingroup$
I've done a little bit of programming in the past, mostly just dabbling.
After a long time of not touching an IDE, I am getting back into it, with Visual Studio. I just threw this quick project together to make sure I remember how to use classes and objects before I start playing with bigger projects.
I would love a quick critique to make sure there arent any glaring poor practices that could develop into bad habbits in the future.
I know the standard way to solve this problem is just time = distance/(velA+velB), but what would the point of using objects be if i didnt have the objects do something and change their status in someway?
What do you think, looks good?
/*
The goal for this practice program is to solve the common math word problem below using classes and objects.
I feel that using iterations rather than the basic math formula to solve, although clearly less efficient, would be more true to thinking in terms of objects.
Train A, traveling X miles per hour (mph), leaves Westford heading toward Eastford, 260 miles away.
At the same time Train B, traveling Y mph, leaves Eastford heading toward Westford.
When do the two trains meet? How far from each city do they meet?
*/
#include "pch.h"
#include <iostream>
using namespace std;
class Train
public:
Train(int, int);
int getLocation();
void update();
private:
int location, velocity;
;
Train::Train(int loc, int vel) //to initialize the train object and set its location and velocity
location = loc;
velocity = vel;
int Train::getLocation() // returns the location of the train object
return location;
void Train::update() // updates the train object for one iteration
location += velocity;
int main()
int velA, velB, distance; //to take the values from the user input
int time; // to keep track of the number of iterations
// time is declared here so it can be used outside of the for loop
//input
cout << "Enter velocity of the train from Westford:n";
cin >> velA;
cout << "nnEnter velocity of the train from Eastford:n";
cin >> velB;
cout << "nnEnter the distance between Westford and Eastford:n";
cin >> distance;
//initialize each train
Train trainA(0, velA);
Train trainB(distance, 0 - velB); //location of trainB is distance because the distance between an x coordinate at 0 and another x coordinate is equal to the second x coordinate
//the velocity of trainB is the negative of velB because it is traveling in the opposite direction of trainA
//run the sim
for (time = 0; trainA.getLocation() < trainB.getLocation(); time++)
trainA.update();
trainB.update();
//output
cout << "nnThe Trains pass eachother after " << time << " hours."
<< "nAt that time, the Westford train is " << trainA.getLocation() << " miles from Westfordn"
<< "and the Eastford train is " << distance - trainB.getLocation() << " miles from Eastford.nn";
return 0;
c++ beginner c++17
New contributor
$endgroup$
$begingroup$
I guess a do while loop could make more sense here than a for loop?
$endgroup$
– Mickey Brenneman
23 mins ago
add a comment |
$begingroup$
I've done a little bit of programming in the past, mostly just dabbling.
After a long time of not touching an IDE, I am getting back into it, with Visual Studio. I just threw this quick project together to make sure I remember how to use classes and objects before I start playing with bigger projects.
I would love a quick critique to make sure there arent any glaring poor practices that could develop into bad habbits in the future.
I know the standard way to solve this problem is just time = distance/(velA+velB), but what would the point of using objects be if i didnt have the objects do something and change their status in someway?
What do you think, looks good?
/*
The goal for this practice program is to solve the common math word problem below using classes and objects.
I feel that using iterations rather than the basic math formula to solve, although clearly less efficient, would be more true to thinking in terms of objects.
Train A, traveling X miles per hour (mph), leaves Westford heading toward Eastford, 260 miles away.
At the same time Train B, traveling Y mph, leaves Eastford heading toward Westford.
When do the two trains meet? How far from each city do they meet?
*/
#include "pch.h"
#include <iostream>
using namespace std;
class Train
public:
Train(int, int);
int getLocation();
void update();
private:
int location, velocity;
;
Train::Train(int loc, int vel) //to initialize the train object and set its location and velocity
location = loc;
velocity = vel;
int Train::getLocation() // returns the location of the train object
return location;
void Train::update() // updates the train object for one iteration
location += velocity;
int main()
int velA, velB, distance; //to take the values from the user input
int time; // to keep track of the number of iterations
// time is declared here so it can be used outside of the for loop
//input
cout << "Enter velocity of the train from Westford:n";
cin >> velA;
cout << "nnEnter velocity of the train from Eastford:n";
cin >> velB;
cout << "nnEnter the distance between Westford and Eastford:n";
cin >> distance;
//initialize each train
Train trainA(0, velA);
Train trainB(distance, 0 - velB); //location of trainB is distance because the distance between an x coordinate at 0 and another x coordinate is equal to the second x coordinate
//the velocity of trainB is the negative of velB because it is traveling in the opposite direction of trainA
//run the sim
for (time = 0; trainA.getLocation() < trainB.getLocation(); time++)
trainA.update();
trainB.update();
//output
cout << "nnThe Trains pass eachother after " << time << " hours."
<< "nAt that time, the Westford train is " << trainA.getLocation() << " miles from Westfordn"
<< "and the Eastford train is " << distance - trainB.getLocation() << " miles from Eastford.nn";
return 0;
c++ beginner c++17
New contributor
$endgroup$
I've done a little bit of programming in the past, mostly just dabbling.
After a long time of not touching an IDE, I am getting back into it, with Visual Studio. I just threw this quick project together to make sure I remember how to use classes and objects before I start playing with bigger projects.
I would love a quick critique to make sure there arent any glaring poor practices that could develop into bad habbits in the future.
I know the standard way to solve this problem is just time = distance/(velA+velB), but what would the point of using objects be if i didnt have the objects do something and change their status in someway?
What do you think, looks good?
/*
The goal for this practice program is to solve the common math word problem below using classes and objects.
I feel that using iterations rather than the basic math formula to solve, although clearly less efficient, would be more true to thinking in terms of objects.
Train A, traveling X miles per hour (mph), leaves Westford heading toward Eastford, 260 miles away.
At the same time Train B, traveling Y mph, leaves Eastford heading toward Westford.
When do the two trains meet? How far from each city do they meet?
*/
#include "pch.h"
#include <iostream>
using namespace std;
class Train
public:
Train(int, int);
int getLocation();
void update();
private:
int location, velocity;
;
Train::Train(int loc, int vel) //to initialize the train object and set its location and velocity
location = loc;
velocity = vel;
int Train::getLocation() // returns the location of the train object
return location;
void Train::update() // updates the train object for one iteration
location += velocity;
int main()
int velA, velB, distance; //to take the values from the user input
int time; // to keep track of the number of iterations
// time is declared here so it can be used outside of the for loop
//input
cout << "Enter velocity of the train from Westford:n";
cin >> velA;
cout << "nnEnter velocity of the train from Eastford:n";
cin >> velB;
cout << "nnEnter the distance between Westford and Eastford:n";
cin >> distance;
//initialize each train
Train trainA(0, velA);
Train trainB(distance, 0 - velB); //location of trainB is distance because the distance between an x coordinate at 0 and another x coordinate is equal to the second x coordinate
//the velocity of trainB is the negative of velB because it is traveling in the opposite direction of trainA
//run the sim
for (time = 0; trainA.getLocation() < trainB.getLocation(); time++)
trainA.update();
trainB.update();
//output
cout << "nnThe Trains pass eachother after " << time << " hours."
<< "nAt that time, the Westford train is " << trainA.getLocation() << " miles from Westfordn"
<< "and the Eastford train is " << distance - trainB.getLocation() << " miles from Eastford.nn";
return 0;
c++ beginner c++17
c++ beginner c++17
New contributor
New contributor
edited 3 mins ago
200_success
130k17154419
130k17154419
New contributor
asked 1 hour ago
Mickey BrennemanMickey Brenneman
61
61
New contributor
New contributor
$begingroup$
I guess a do while loop could make more sense here than a for loop?
$endgroup$
– Mickey Brenneman
23 mins ago
add a comment |
$begingroup$
I guess a do while loop could make more sense here than a for loop?
$endgroup$
– Mickey Brenneman
23 mins ago
$begingroup$
I guess a do while loop could make more sense here than a for loop?
$endgroup$
– Mickey Brenneman
23 mins ago
$begingroup$
I guess a do while loop could make more sense here than a for loop?
$endgroup$
– Mickey Brenneman
23 mins ago
add a comment |
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$begingroup$
I guess a do while loop could make more sense here than a for loop?
$endgroup$
– Mickey Brenneman
23 mins ago