Finding the numerically listed string to the center algorthimPattern Matching with MismatchPrint all permutations with repetition of charactersPrint all subsets and permutations of a stringChecking if all the characters from an A-Z is present in the stringFinding the first non-repeating character in a stringFinding longest substring containing k distinct charactersA sequence of mistakesConcatenating two substrings to provide the largest possible palindromic stringFinding longest common prefixGiven a large string, finding the length of the first longest even length sub-string

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Finding the numerically listed string to the center algorthim


Pattern Matching with MismatchPrint all permutations with repetition of charactersPrint all subsets and permutations of a stringChecking if all the characters from an A-Z is present in the stringFinding the first non-repeating character in a stringFinding longest substring containing k distinct charactersA sequence of mistakesConcatenating two substrings to provide the largest possible palindromic stringFinding longest common prefixGiven a large string, finding the length of the first longest even length sub-string













0












$begingroup$


The algorithm takes input for a string's length for L, and the number of strings altogether for X. The hamming distance is for input D. Input Z calculates the exact amount of all possible characters in the string besides the permutations for input D.



We get a set of Z amount of characters. We divide Z by D which is S. We get B possible permutations of characters that can be generated in a list of X strings. In other words, Z divided by Y groupings of the same X should uniquely have B possible permutations within the Z characters. (For the center numerical listed string based on hamming?)



If the algorithm is, correct (or I've misled). The center of Z is at the S string which should be the B permutation.



NOTE: The concept is to visualize our strings as a number line.



Here the algorithm is written in Ancient Basic from a TRS-80 computer.



0 A=1
1 INPUT "LENGTH OF STRING";L
2 INPUT "X FOR HOW MANY";X
3 INPUT "D FOR HAMMING DISTANCE";D
4 Z = X * X * 1 * L + X * D * D * D
5 S = Z / D
6 B = S / D
7 Y = S / B
8 CL = D * A ≤ X ≤ B * Y
10 P=B*Y
11 PRINT "CLOSEST STRING", CL, "P=", P
12 IF S = S * D / D THEN PRINT"S = S * D / D", S * D / D
13 IF D = Z / S THEN PRINT"D = Z / S", Z / S
15 PRINT"PROOF", P, S


I also continue with the algorithm to find where the 2nd closest string, 3rd closest, 4th and so on.



16 PRINT"WOULD YOU LIKE TO FIND CUSTOM CLOSEST STRING?";R$
17 IF R$=YES$ THEN GOTO 19
18 IF R$=NO$ THEN GOTO 19
19 INPUT "ENTER # FOR CLSE STRING";RT
20 GOTO 21
21 PRINT"YOUR CLOSEST STRING"RT, S / RT
90 NQ = S / RT
91 P = RT * NQ
92 IF P = NC THEN PRINT P, NC, "LUCKY"








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$endgroup$
















    0












    $begingroup$


    The algorithm takes input for a string's length for L, and the number of strings altogether for X. The hamming distance is for input D. Input Z calculates the exact amount of all possible characters in the string besides the permutations for input D.



    We get a set of Z amount of characters. We divide Z by D which is S. We get B possible permutations of characters that can be generated in a list of X strings. In other words, Z divided by Y groupings of the same X should uniquely have B possible permutations within the Z characters. (For the center numerical listed string based on hamming?)



    If the algorithm is, correct (or I've misled). The center of Z is at the S string which should be the B permutation.



    NOTE: The concept is to visualize our strings as a number line.



    Here the algorithm is written in Ancient Basic from a TRS-80 computer.



    0 A=1
    1 INPUT "LENGTH OF STRING";L
    2 INPUT "X FOR HOW MANY";X
    3 INPUT "D FOR HAMMING DISTANCE";D
    4 Z = X * X * 1 * L + X * D * D * D
    5 S = Z / D
    6 B = S / D
    7 Y = S / B
    8 CL = D * A ≤ X ≤ B * Y
    10 P=B*Y
    11 PRINT "CLOSEST STRING", CL, "P=", P
    12 IF S = S * D / D THEN PRINT"S = S * D / D", S * D / D
    13 IF D = Z / S THEN PRINT"D = Z / S", Z / S
    15 PRINT"PROOF", P, S


    I also continue with the algorithm to find where the 2nd closest string, 3rd closest, 4th and so on.



    16 PRINT"WOULD YOU LIKE TO FIND CUSTOM CLOSEST STRING?";R$
    17 IF R$=YES$ THEN GOTO 19
    18 IF R$=NO$ THEN GOTO 19
    19 INPUT "ENTER # FOR CLSE STRING";RT
    20 GOTO 21
    21 PRINT"YOUR CLOSEST STRING"RT, S / RT
    90 NQ = S / RT
    91 P = RT * NQ
    92 IF P = NC THEN PRINT P, NC, "LUCKY"








    share







    New contributor




    Travis Wells is a new contributor to this site. Take care in asking for clarification, commenting, and answering.
    Check out our Code of Conduct.







    $endgroup$














      0












      0








      0





      $begingroup$


      The algorithm takes input for a string's length for L, and the number of strings altogether for X. The hamming distance is for input D. Input Z calculates the exact amount of all possible characters in the string besides the permutations for input D.



      We get a set of Z amount of characters. We divide Z by D which is S. We get B possible permutations of characters that can be generated in a list of X strings. In other words, Z divided by Y groupings of the same X should uniquely have B possible permutations within the Z characters. (For the center numerical listed string based on hamming?)



      If the algorithm is, correct (or I've misled). The center of Z is at the S string which should be the B permutation.



      NOTE: The concept is to visualize our strings as a number line.



      Here the algorithm is written in Ancient Basic from a TRS-80 computer.



      0 A=1
      1 INPUT "LENGTH OF STRING";L
      2 INPUT "X FOR HOW MANY";X
      3 INPUT "D FOR HAMMING DISTANCE";D
      4 Z = X * X * 1 * L + X * D * D * D
      5 S = Z / D
      6 B = S / D
      7 Y = S / B
      8 CL = D * A ≤ X ≤ B * Y
      10 P=B*Y
      11 PRINT "CLOSEST STRING", CL, "P=", P
      12 IF S = S * D / D THEN PRINT"S = S * D / D", S * D / D
      13 IF D = Z / S THEN PRINT"D = Z / S", Z / S
      15 PRINT"PROOF", P, S


      I also continue with the algorithm to find where the 2nd closest string, 3rd closest, 4th and so on.



      16 PRINT"WOULD YOU LIKE TO FIND CUSTOM CLOSEST STRING?";R$
      17 IF R$=YES$ THEN GOTO 19
      18 IF R$=NO$ THEN GOTO 19
      19 INPUT "ENTER # FOR CLSE STRING";RT
      20 GOTO 21
      21 PRINT"YOUR CLOSEST STRING"RT, S / RT
      90 NQ = S / RT
      91 P = RT * NQ
      92 IF P = NC THEN PRINT P, NC, "LUCKY"








      share







      New contributor




      Travis Wells is a new contributor to this site. Take care in asking for clarification, commenting, and answering.
      Check out our Code of Conduct.







      $endgroup$




      The algorithm takes input for a string's length for L, and the number of strings altogether for X. The hamming distance is for input D. Input Z calculates the exact amount of all possible characters in the string besides the permutations for input D.



      We get a set of Z amount of characters. We divide Z by D which is S. We get B possible permutations of characters that can be generated in a list of X strings. In other words, Z divided by Y groupings of the same X should uniquely have B possible permutations within the Z characters. (For the center numerical listed string based on hamming?)



      If the algorithm is, correct (or I've misled). The center of Z is at the S string which should be the B permutation.



      NOTE: The concept is to visualize our strings as a number line.



      Here the algorithm is written in Ancient Basic from a TRS-80 computer.



      0 A=1
      1 INPUT "LENGTH OF STRING";L
      2 INPUT "X FOR HOW MANY";X
      3 INPUT "D FOR HAMMING DISTANCE";D
      4 Z = X * X * 1 * L + X * D * D * D
      5 S = Z / D
      6 B = S / D
      7 Y = S / B
      8 CL = D * A ≤ X ≤ B * Y
      10 P=B*Y
      11 PRINT "CLOSEST STRING", CL, "P=", P
      12 IF S = S * D / D THEN PRINT"S = S * D / D", S * D / D
      13 IF D = Z / S THEN PRINT"D = Z / S", Z / S
      15 PRINT"PROOF", P, S


      I also continue with the algorithm to find where the 2nd closest string, 3rd closest, 4th and so on.



      16 PRINT"WOULD YOU LIKE TO FIND CUSTOM CLOSEST STRING?";R$
      17 IF R$=YES$ THEN GOTO 19
      18 IF R$=NO$ THEN GOTO 19
      19 INPUT "ENTER # FOR CLSE STRING";RT
      20 GOTO 21
      21 PRINT"YOUR CLOSEST STRING"RT, S / RT
      90 NQ = S / RT
      91 P = RT * NQ
      92 IF P = NC THEN PRINT P, NC, "LUCKY"






      strings basic-lang





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      Check out our Code of Conduct.










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      asked 3 mins ago









      Travis WellsTravis Wells

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      Travis Wells is a new contributor to this site. Take care in asking for clarification, commenting, and answering.
      Check out our Code of Conduct.






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      Check out our Code of Conduct.




















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