Extracting grouped objects into a flattened list The Next CEO of Stack OverflowNested Google Maps ListenerObject-oriented JavaScript and Google Maps objects memory managementReduce array of objects into object of arraysReducing a large array of objects to a simple object with 8 propertiesCalculate average of array of objects per key value using reduceES6 Javascript (React) code that maps and filters JSON dataCreating nested objects from stringFilter array of objects by comparing nested object propertiesExecute promise tree in order of declarationOptimized pulling items out of arrays in nested objects
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Extracting grouped objects into a flattened list
The Next CEO of Stack OverflowNested Google Maps ListenerObject-oriented JavaScript and Google Maps objects memory managementReduce array of objects into object of arraysReducing a large array of objects to a simple object with 8 propertiesCalculate average of array of objects per key value using reduceES6 Javascript (React) code that maps and filters JSON dataCreating nested objects from stringFilter array of objects by comparing nested object propertiesExecute promise tree in order of declarationOptimized pulling items out of arrays in nested objects
0
$begingroup$
I need to optimize this javascript method because it is a bit slow, I don't want to use the flat() command, as for some reason my angular6 app does not understand the vanilla flat() command, or display some annoying warning messages.
So check the below:
- my original object
- my result object desired
- my slow solution (works, but is slow)
1. my original object:
const data = [
"id": 1,
"name": "Application",
"groups": [
"groupName": "",
"configurations": [
"id": 17,
"icon": "access_time",
"title": "Daily Order Cut-Off Time",
"description": "Daily Order Cut-Off Time",
"code": "daily-order-cut-off-time",
"value": "09:35",
"valueType": "Time",
"configurationTypeId": 11,
"definition":
"step": "none"
,
"isDefault": false
]
]
,
"id": 3,
"name": "Processing",
"groups": [
"groupName": "",
"configurations": [
"id": 1078,
"icon": "flash_on",
"title": "Auto Process",
"description": "Will process all orders that are in the same batch",
"code": "processing-auto-process",
"value": "0",
"valueType": "Boolean",
"configurationTypeId": 6,
"definition": null,
"isDefault": false
,
"id": 1074,
"icon": "subdirectory_arrow_right",
"title": "Allow Under Picking",
"description": "Allow under pick when processing order?",
"code": "processing-allow-under-picks",
"value": "0",
"valueType": "Boolean",
"configurationTypeId": 6,
"definition": null,
"isDefault": false
]
]
];
2. object desired:
[
"id": 17,
"code": "daily-order-cut-off-time",
"value": "09:35"
,
"id": 1078,
"code": "processing-auto-process",
"value": "0"
,
"id": 1074,
"code": "processing-allow-under-picks",
"value": "0"
]
My slow solution:
const result = data.map(module => module.groups.map(configurations => configurations.configurations.map(config => ( id: config.id, code: config.code, value: config.value )))).reduce((l,n) => l.concat(n), []).reduce((l2,n2) => l2.concat(n2),[]));
javascript ecmascript-6
edited 1 min ago
200_success
130k17155419
asked 6 hours ago
Roger OliveiraRoger Oliveira
150111
$endgroup$
add a comment |
0
$begingroup$
I need to optimize this javascript method because it is a bit slow, I don't want to use the flat() command, as for some reason my angular6 app does not understand the vanilla flat() command, or display some annoying warning messages.
So check the below:
- my original object
- my result object desired
- my slow solution (works, but is slow)
1. my original object:
const data = [
"id": 1,
"name": "Application",
"groups": [
"groupName": "",
"configurations": [
"id": 17,
"icon": "access_time",
"title": "Daily Order Cut-Off Time",
"description": "Daily Order Cut-Off Time",
"code": "daily-order-cut-off-time",
"value": "09:35",
"valueType": "Time",
"configurationTypeId": 11,
"definition":
"step": "none"
,
"isDefault": false
]
]
,
"id": 3,
"name": "Processing",
"groups": [
"groupName": "",
"configurations": [
"id": 1078,
"icon": "flash_on",
"title": "Auto Process",
"description": "Will process all orders that are in the same batch",
"code": "processing-auto-process",
"value": "0",
"valueType": "Boolean",
"configurationTypeId": 6,
"definition": null,
"isDefault": false
,
"id": 1074,
"icon": "subdirectory_arrow_right",
"title": "Allow Under Picking",
"description": "Allow under pick when processing order?",
"code": "processing-allow-under-picks",
"value": "0",
"valueType": "Boolean",
"configurationTypeId": 6,
"definition": null,
"isDefault": false
]
]
];
2. object desired:
[
"id": 17,
"code": "daily-order-cut-off-time",
"value": "09:35"
,
"id": 1078,
"code": "processing-auto-process",
"value": "0"
,
"id": 1074,
"code": "processing-allow-under-picks",
"value": "0"
]
My slow solution:
const result = data.map(module => module.groups.map(configurations => configurations.configurations.map(config => ( id: config.id, code: config.code, value: config.value )))).reduce((l,n) => l.concat(n), []).reduce((l2,n2) => l2.concat(n2),[]));
javascript ecmascript-6
edited 1 min ago
200_success
130k17155419
asked 6 hours ago
Roger OliveiraRoger Oliveira
150111
$endgroup$
2
$begingroup$
Is the ES6 spread operator available to you?result = [].concat(...[].concat(...data.map( d => d.groups.map( g => g.configurations.map( c => (id:c.id, code:c.code, value:c.value))))))
$endgroup$
– Oh My Goodness
5 hours ago
$begingroup$
yes it is available.
$endgroup$
– Roger Oliveira
5 hours ago
$begingroup$
AMAZING! YOUR CODE IS BEAUTIFUL!, please answer my question I will mark as the correct answer!
$endgroup$
– Roger Oliveira
5 hours ago
add a comment |
0
0
0
1
$begingroup$
I need to optimize this javascript method because it is a bit slow, I don't want to use the flat() command, as for some reason my angular6 app does not understand the vanilla flat() command, or display some annoying warning messages.
So check the below:
- my original object
- my result object desired
- my slow solution (works, but is slow)
1. my original object:
const data = [
"id": 1,
"name": "Application",
"groups": [
"groupName": "",
"configurations": [
"id": 17,
"icon": "access_time",
"title": "Daily Order Cut-Off Time",
"description": "Daily Order Cut-Off Time",
"code": "daily-order-cut-off-time",
"value": "09:35",
"valueType": "Time",
"configurationTypeId": 11,
"definition":
"step": "none"
,
"isDefault": false
]
]
,
"id": 3,
"name": "Processing",
"groups": [
"groupName": "",
"configurations": [
"id": 1078,
"icon": "flash_on",
"title": "Auto Process",
"description": "Will process all orders that are in the same batch",
"code": "processing-auto-process",
"value": "0",
"valueType": "Boolean",
"configurationTypeId": 6,
"definition": null,
"isDefault": false
,
"id": 1074,
"icon": "subdirectory_arrow_right",
"title": "Allow Under Picking",
"description": "Allow under pick when processing order?",
"code": "processing-allow-under-picks",
"value": "0",
"valueType": "Boolean",
"configurationTypeId": 6,
"definition": null,
"isDefault": false
]
]
];
2. object desired:
[
"id": 17,
"code": "daily-order-cut-off-time",
"value": "09:35"
,
"id": 1078,
"code": "processing-auto-process",
"value": "0"
,
"id": 1074,
"code": "processing-allow-under-picks",
"value": "0"
]
My slow solution:
const result = data.map(module => module.groups.map(configurations => configurations.configurations.map(config => ( id: config.id, code: config.code, value: config.value )))).reduce((l,n) => l.concat(n), []).reduce((l2,n2) => l2.concat(n2),[]));
javascript ecmascript-6
edited 1 min ago
200_success
130k17155419
asked 6 hours ago
Roger OliveiraRoger Oliveira
150111
$endgroup$
I need to optimize this javascript method because it is a bit slow, I don't want to use the flat() command, as for some reason my angular6 app does not understand the vanilla flat() command, or display some annoying warning messages.
So check the below:
- my original object
- my result object desired
- my slow solution (works, but is slow)
1. my original object:
const data = [
"id": 1,
"name": "Application",
"groups": [
"groupName": "",
"configurations": [
"id": 17,
"icon": "access_time",
"title": "Daily Order Cut-Off Time",
"description": "Daily Order Cut-Off Time",
"code": "daily-order-cut-off-time",
"value": "09:35",
"valueType": "Time",
"configurationTypeId": 11,
"definition":
"step": "none"
,
"isDefault": false
]
]
,
"id": 3,
"name": "Processing",
"groups": [
"groupName": "",
"configurations": [
"id": 1078,
"icon": "flash_on",
"title": "Auto Process",
"description": "Will process all orders that are in the same batch",
"code": "processing-auto-process",
"value": "0",
"valueType": "Boolean",
"configurationTypeId": 6,
"definition": null,
"isDefault": false
,
"id": 1074,
"icon": "subdirectory_arrow_right",
"title": "Allow Under Picking",
"description": "Allow under pick when processing order?",
"code": "processing-allow-under-picks",
"value": "0",
"valueType": "Boolean",
"configurationTypeId": 6,
"definition": null,
"isDefault": false
]
]
];
2. object desired:
[
"id": 17,
"code": "daily-order-cut-off-time",
"value": "09:35"
,
"id": 1078,
"code": "processing-auto-process",
"value": "0"
,
"id": 1074,
"code": "processing-allow-under-picks",
"value": "0"
]
My slow solution:
const result = data.map(module => module.groups.map(configurations => configurations.configurations.map(config => ( id: config.id, code: config.code, value: config.value )))).reduce((l,n) => l.concat(n), []).reduce((l2,n2) => l2.concat(n2),[]));
javascript ecmascript-6
javascript ecmascript-6
edited 1 min ago
200_success
130k17155419
asked 6 hours ago
Roger OliveiraRoger Oliveira
150111
edited 1 min ago
200_success
130k17155419
asked 6 hours ago
Roger OliveiraRoger Oliveira
150111
edited 1 min ago
200_success
130k17155419
edited 1 min ago
200_success
130k17155419
edited 1 min ago
200_success
130k17155419
130k17155419
asked 6 hours ago
Roger OliveiraRoger Oliveira
150111
asked 6 hours ago
Roger OliveiraRoger Oliveira
150111
asked 6 hours ago
Roger OliveiraRoger Oliveira
150111
150111
2
$begingroup$
Is the ES6 spread operator available to you?result = [].concat(...[].concat(...data.map( d => d.groups.map( g => g.configurations.map( c => (id:c.id, code:c.code, value:c.value))))))
$endgroup$
– Oh My Goodness
5 hours ago
$begingroup$
yes it is available.
$endgroup$
– Roger Oliveira
5 hours ago
$begingroup$
AMAZING! YOUR CODE IS BEAUTIFUL!, please answer my question I will mark as the correct answer!
$endgroup$
– Roger Oliveira
5 hours ago
add a comment |
2
$begingroup$
Is the ES6 spread operator available to you?result = [].concat(...[].concat(...data.map( d => d.groups.map( g => g.configurations.map( c => (id:c.id, code:c.code, value:c.value))))))
$endgroup$
– Oh My Goodness
5 hours ago
$begingroup$
yes it is available.
$endgroup$
– Roger Oliveira
5 hours ago
$begingroup$
AMAZING! YOUR CODE IS BEAUTIFUL!, please answer my question I will mark as the correct answer!
$endgroup$
– Roger Oliveira
5 hours ago
2
2
$begingroup$
Is the ES6 spread operator available to you?
result = [].concat(...[].concat(...data.map( d => d.groups.map( g => g.configurations.map( c => (id:c.id, code:c.code, value:c.value))))))$endgroup$
– Oh My Goodness
5 hours ago
$begingroup$
Is the ES6 spread operator available to you?
result = [].concat(...[].concat(...data.map( d => d.groups.map( g => g.configurations.map( c => (id:c.id, code:c.code, value:c.value))))))$endgroup$
– Oh My Goodness
5 hours ago
$begingroup$
yes it is available.
$endgroup$
– Roger Oliveira
5 hours ago
$begingroup$
yes it is available.
$endgroup$
– Roger Oliveira
5 hours ago
$begingroup$
AMAZING! YOUR CODE IS BEAUTIFUL!, please answer my question I will mark as the correct answer!
$endgroup$
– Roger Oliveira
5 hours ago
$begingroup$
AMAZING! YOUR CODE IS BEAUTIFUL!, please answer my question I will mark as the correct answer!
$endgroup$
– Roger Oliveira
5 hours ago
add a comment |
1 Answer
1
active
oldest
votes
2
$begingroup$
As commented, the ES6 spread operator flattens like you want. The syntax is a little weird for multiple invocations:
result = [].concat(...[].concat(...data.map( d => d.groups.map( g => g.configurations.map( c => (id:c.id, code:c.code, value:c.value))))))
answered 5 hours ago
Oh My GoodnessOh My Goodness
1,874314
$endgroup$
$begingroup$
also, the use of the command .flat() would help somehow in this solution? thanks.
$endgroup$
– Roger Oliveira
2 hours ago
add a comment |
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1 Answer
1
active
oldest
votes
active
oldest
votes
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oldest
votes
2
$begingroup$
As commented, the ES6 spread operator flattens like you want. The syntax is a little weird for multiple invocations:
result = [].concat(...[].concat(...data.map( d => d.groups.map( g => g.configurations.map( c => (id:c.id, code:c.code, value:c.value))))))
answered 5 hours ago
Oh My GoodnessOh My Goodness
1,874314
$endgroup$
$begingroup$
also, the use of the command .flat() would help somehow in this solution? thanks.
$endgroup$
– Roger Oliveira
2 hours ago
add a comment |
2
$begingroup$
As commented, the ES6 spread operator flattens like you want. The syntax is a little weird for multiple invocations:
result = [].concat(...[].concat(...data.map( d => d.groups.map( g => g.configurations.map( c => (id:c.id, code:c.code, value:c.value))))))
answered 5 hours ago
Oh My GoodnessOh My Goodness
1,874314
$endgroup$
$begingroup$
also, the use of the command .flat() would help somehow in this solution? thanks.
$endgroup$
– Roger Oliveira
2 hours ago
add a comment |
2
2
2
$begingroup$
As commented, the ES6 spread operator flattens like you want. The syntax is a little weird for multiple invocations:
result = [].concat(...[].concat(...data.map( d => d.groups.map( g => g.configurations.map( c => (id:c.id, code:c.code, value:c.value))))))
answered 5 hours ago
Oh My GoodnessOh My Goodness
1,874314
$endgroup$
As commented, the ES6 spread operator flattens like you want. The syntax is a little weird for multiple invocations:
result = [].concat(...[].concat(...data.map( d => d.groups.map( g => g.configurations.map( c => (id:c.id, code:c.code, value:c.value))))))
answered 5 hours ago
Oh My GoodnessOh My Goodness
1,874314
answered 5 hours ago
Oh My GoodnessOh My Goodness
1,874314
answered 5 hours ago
Oh My GoodnessOh My Goodness
1,874314
answered 5 hours ago
Oh My GoodnessOh My Goodness
1,874314
1,874314
$begingroup$
also, the use of the command .flat() would help somehow in this solution? thanks.
$endgroup$
– Roger Oliveira
2 hours ago
add a comment |
$begingroup$
also, the use of the command .flat() would help somehow in this solution? thanks.
$endgroup$
– Roger Oliveira
2 hours ago
$begingroup$
also, the use of the command .flat() would help somehow in this solution? thanks.
$endgroup$
– Roger Oliveira
2 hours ago
$begingroup$
also, the use of the command .flat() would help somehow in this solution? thanks.
$endgroup$
– Roger Oliveira
2 hours ago
add a comment |
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2
$begingroup$
Is the ES6 spread operator available to you?
result = [].concat(...[].concat(...data.map( d => d.groups.map( g => g.configurations.map( c => (id:c.id, code:c.code, value:c.value))))))$endgroup$
– Oh My Goodness
5 hours ago
$begingroup$
yes it is available.
$endgroup$
– Roger Oliveira
5 hours ago
$begingroup$
AMAZING! YOUR CODE IS BEAUTIFUL!, please answer my question I will mark as the correct answer!
$endgroup$
– Roger Oliveira
5 hours ago