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How to read string as hex number in bash?
2019 Community Moderator ElectionIn bash, how to convert 8 bytes to an unsigned int (64bit LE)?Bash: integer expression expected, using read/testHow to change bash prompt string in current bash session?How to convert an special hex character from an html page in bash?Loop over a string in zsh and BashModifying empty string variable inside switch statement in function bashExtract Complex String Inside Parentheses in Linux BashConstruct bash array with only string formatprintf escape %q string vs variableHow are ext4fs checksums being calculated?
I have the bash line:
expr substr $SUPERBLOCK 64 8
Which is return to me string line:
00080000
I know that this is, actually, a 0x00080000 in little-endian. Is there a way to create integer-variable from it in bash in big-endian like 0x80000?
bash numeric-data hex expr
edited 3 hours ago
Jesse_b
13.7k23371
asked 4 hours ago
DenisNovacDenisNovac
186
add a comment |
I have the bash line:
expr substr $SUPERBLOCK 64 8
Which is return to me string line:
00080000
I know that this is, actually, a 0x00080000 in little-endian. Is there a way to create integer-variable from it in bash in big-endian like 0x80000?
bash numeric-data hex expr
edited 3 hours ago
Jesse_b
13.7k23371
asked 4 hours ago
DenisNovacDenisNovac
186
add a comment |
I have the bash line:
expr substr $SUPERBLOCK 64 8
Which is return to me string line:
00080000
I know that this is, actually, a 0x00080000 in little-endian. Is there a way to create integer-variable from it in bash in big-endian like 0x80000?
bash numeric-data hex expr
edited 3 hours ago
Jesse_b
13.7k23371
asked 4 hours ago
DenisNovacDenisNovac
186
I have the bash line:
expr substr $SUPERBLOCK 64 8
Which is return to me string line:
00080000
I know that this is, actually, a 0x00080000 in little-endian. Is there a way to create integer-variable from it in bash in big-endian like 0x80000?
bash numeric-data hex expr
bash numeric-data hex expr
edited 3 hours ago
Jesse_b
13.7k23371
asked 4 hours ago
DenisNovacDenisNovac
186
edited 3 hours ago
Jesse_b
13.7k23371
asked 4 hours ago
DenisNovacDenisNovac
186
edited 3 hours ago
Jesse_b
13.7k23371
edited 3 hours ago
Jesse_b
13.7k23371
edited 3 hours ago
Jesse_b
13.7k23371
13.7k23371
asked 4 hours ago
DenisNovacDenisNovac
186
asked 4 hours ago
DenisNovacDenisNovac
186
asked 4 hours ago
DenisNovacDenisNovac
186
186
add a comment |
add a comment |
1 Answer
1
active
oldest
votes
Probably a better way to do this but I've come up with this solution which converts the number to decimal and then back to hex (and manually adds the 0x):
printf '0x%xn' "$((16#00080000))"
Which you could write as:
printf '0x%xn' "$((16#$(expr substr "$SUPERBLOCK" 64 8)))"
answered 3 hours ago
Jesse_bJesse_b
13.7k23371
Thank you! I actually added |rev inside to convert to big-endian: printf "$((16#$(expr substr $SUPERBLOCK 64 8|rev)))"
– DenisNovac
3 hours ago
4
@DenisNovac I'm not sure if you use big/little endian correctly (maybe you have something else on mind, but I'm doing some assembly programming for fun, so for me endianness is per bytes), but 0x12345678 is in other endianness 0x78563412, not 0x87654321. (and the value in your question00080000is after byte swap00000800, i.e. 2048 decimal)
– Ped7g
3 hours ago
Oh, you are right. I just got the right answer by wrong way. I am rewriting some code from python to bash, so i know all answers before i got them.
– DenisNovac
3 hours ago
@DenisNovac: You didn't have the right answer FYI. 0x8000 was originally in your question which is not the same as 0x80000 or 0x00080000
– Jesse_b
3 hours ago
Yes, but i needed to get exactly 0x8000, so i've made mistake somewhere before. This is offset or something.
– DenisNovac
3 hours ago
|
show 4 more comments
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1 Answer
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1 Answer
1
active
oldest
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oldest
votes
active
oldest
votes
Probably a better way to do this but I've come up with this solution which converts the number to decimal and then back to hex (and manually adds the 0x):
printf '0x%xn' "$((16#00080000))"
Which you could write as:
printf '0x%xn' "$((16#$(expr substr "$SUPERBLOCK" 64 8)))"
answered 3 hours ago
Jesse_bJesse_b
13.7k23371
Thank you! I actually added |rev inside to convert to big-endian: printf "$((16#$(expr substr $SUPERBLOCK 64 8|rev)))"
– DenisNovac
3 hours ago
4
@DenisNovac I'm not sure if you use big/little endian correctly (maybe you have something else on mind, but I'm doing some assembly programming for fun, so for me endianness is per bytes), but 0x12345678 is in other endianness 0x78563412, not 0x87654321. (and the value in your question00080000is after byte swap00000800, i.e. 2048 decimal)
– Ped7g
3 hours ago
Oh, you are right. I just got the right answer by wrong way. I am rewriting some code from python to bash, so i know all answers before i got them.
– DenisNovac
3 hours ago
@DenisNovac: You didn't have the right answer FYI. 0x8000 was originally in your question which is not the same as 0x80000 or 0x00080000
– Jesse_b
3 hours ago
Yes, but i needed to get exactly 0x8000, so i've made mistake somewhere before. This is offset or something.
– DenisNovac
3 hours ago
|
show 4 more comments
Probably a better way to do this but I've come up with this solution which converts the number to decimal and then back to hex (and manually adds the 0x):
printf '0x%xn' "$((16#00080000))"
Which you could write as:
printf '0x%xn' "$((16#$(expr substr "$SUPERBLOCK" 64 8)))"
answered 3 hours ago
Jesse_bJesse_b
13.7k23371
Thank you! I actually added |rev inside to convert to big-endian: printf "$((16#$(expr substr $SUPERBLOCK 64 8|rev)))"
– DenisNovac
3 hours ago
4
@DenisNovac I'm not sure if you use big/little endian correctly (maybe you have something else on mind, but I'm doing some assembly programming for fun, so for me endianness is per bytes), but 0x12345678 is in other endianness 0x78563412, not 0x87654321. (and the value in your question00080000is after byte swap00000800, i.e. 2048 decimal)
– Ped7g
3 hours ago
Oh, you are right. I just got the right answer by wrong way. I am rewriting some code from python to bash, so i know all answers before i got them.
– DenisNovac
3 hours ago
@DenisNovac: You didn't have the right answer FYI. 0x8000 was originally in your question which is not the same as 0x80000 or 0x00080000
– Jesse_b
3 hours ago
Yes, but i needed to get exactly 0x8000, so i've made mistake somewhere before. This is offset or something.
– DenisNovac
3 hours ago
|
show 4 more comments
Probably a better way to do this but I've come up with this solution which converts the number to decimal and then back to hex (and manually adds the 0x):
printf '0x%xn' "$((16#00080000))"
Which you could write as:
printf '0x%xn' "$((16#$(expr substr "$SUPERBLOCK" 64 8)))"
answered 3 hours ago
Jesse_bJesse_b
13.7k23371
Probably a better way to do this but I've come up with this solution which converts the number to decimal and then back to hex (and manually adds the 0x):
printf '0x%xn' "$((16#00080000))"
Which you could write as:
printf '0x%xn' "$((16#$(expr substr "$SUPERBLOCK" 64 8)))"
answered 3 hours ago
Jesse_bJesse_b
13.7k23371
answered 3 hours ago
Jesse_bJesse_b
13.7k23371
answered 3 hours ago
Jesse_bJesse_b
13.7k23371
answered 3 hours ago
Jesse_bJesse_b
13.7k23371
13.7k23371
Thank you! I actually added |rev inside to convert to big-endian: printf "$((16#$(expr substr $SUPERBLOCK 64 8|rev)))"
– DenisNovac
3 hours ago
4
@DenisNovac I'm not sure if you use big/little endian correctly (maybe you have something else on mind, but I'm doing some assembly programming for fun, so for me endianness is per bytes), but 0x12345678 is in other endianness 0x78563412, not 0x87654321. (and the value in your question00080000is after byte swap00000800, i.e. 2048 decimal)
– Ped7g
3 hours ago
Oh, you are right. I just got the right answer by wrong way. I am rewriting some code from python to bash, so i know all answers before i got them.
– DenisNovac
3 hours ago
@DenisNovac: You didn't have the right answer FYI. 0x8000 was originally in your question which is not the same as 0x80000 or 0x00080000
– Jesse_b
3 hours ago
Yes, but i needed to get exactly 0x8000, so i've made mistake somewhere before. This is offset or something.
– DenisNovac
3 hours ago
|
show 4 more comments
Thank you! I actually added |rev inside to convert to big-endian: printf "$((16#$(expr substr $SUPERBLOCK 64 8|rev)))"
– DenisNovac
3 hours ago
4
@DenisNovac I'm not sure if you use big/little endian correctly (maybe you have something else on mind, but I'm doing some assembly programming for fun, so for me endianness is per bytes), but 0x12345678 is in other endianness 0x78563412, not 0x87654321. (and the value in your question00080000is after byte swap00000800, i.e. 2048 decimal)
– Ped7g
3 hours ago
Oh, you are right. I just got the right answer by wrong way. I am rewriting some code from python to bash, so i know all answers before i got them.
– DenisNovac
3 hours ago
@DenisNovac: You didn't have the right answer FYI. 0x8000 was originally in your question which is not the same as 0x80000 or 0x00080000
– Jesse_b
3 hours ago
Yes, but i needed to get exactly 0x8000, so i've made mistake somewhere before. This is offset or something.
– DenisNovac
3 hours ago
Thank you! I actually added |rev inside to convert to big-endian: printf "$((16#$(expr substr $SUPERBLOCK 64 8|rev)))"
– DenisNovac
3 hours ago
Thank you! I actually added |rev inside to convert to big-endian: printf "$((16#$(expr substr $SUPERBLOCK 64 8|rev)))"
– DenisNovac
3 hours ago
4
4
@DenisNovac I'm not sure if you use big/little endian correctly (maybe you have something else on mind, but I'm doing some assembly programming for fun, so for me endianness is per bytes), but 0x12345678 is in other endianness 0x78563412, not 0x87654321. (and the value in your question
00080000 is after byte swap 00000800, i.e. 2048 decimal)– Ped7g
3 hours ago
@DenisNovac I'm not sure if you use big/little endian correctly (maybe you have something else on mind, but I'm doing some assembly programming for fun, so for me endianness is per bytes), but 0x12345678 is in other endianness 0x78563412, not 0x87654321. (and the value in your question
00080000 is after byte swap 00000800, i.e. 2048 decimal)– Ped7g
3 hours ago
Oh, you are right. I just got the right answer by wrong way. I am rewriting some code from python to bash, so i know all answers before i got them.
– DenisNovac
3 hours ago
Oh, you are right. I just got the right answer by wrong way. I am rewriting some code from python to bash, so i know all answers before i got them.
– DenisNovac
3 hours ago
@DenisNovac: You didn't have the right answer FYI. 0x8000 was originally in your question which is not the same as 0x80000 or 0x00080000
– Jesse_b
3 hours ago
@DenisNovac: You didn't have the right answer FYI. 0x8000 was originally in your question which is not the same as 0x80000 or 0x00080000
– Jesse_b
3 hours ago
Yes, but i needed to get exactly 0x8000, so i've made mistake somewhere before. This is offset or something.
– DenisNovac
3 hours ago
Yes, but i needed to get exactly 0x8000, so i've made mistake somewhere before. This is offset or something.
– DenisNovac
3 hours ago
|
show 4 more comments
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